dict0={'a':1,'a':5,'b':2,'a':8,'c':3}
tuple0=('a','b','c')
# list0=['a','b','c']
set0={'a','b','c',7}

dict1={3:1,4:2}
tuple1=(10,11,12)
list1=[4,5,6]
set1={7,7,8,9}
a='521234'
# print(a.find('5'))
# set0.add(tuple0);print(set0,set1)
# print(set0-set1,set1.difference(set0),set0&set1,set0.intersection(set1),set0|set1,set0.union(set1),set1^set0,set0.symmetric_difference(set1))
# print(set0.intersection_update(set1),set0,set1)
# print(set0.difference_update(set1),set0,set1)
# print(set0.symmetric_difference_update(set1),set0,set1)
# print(dict0,dict1);dict0.update(dict1);print(dict1,dict0)
# int2=asdfksd
# result=int(int1)
# print(result)
# i0=[list0,tuple0,dict0]#,set0
i1=[list1,set1,a,dict1,tuple1]#
# set0={1,0,2,3}
for i in range(5):
	ran=i1[i];print('1' in ran);print(type(ran),ran)#print(set1.update(ran),set1);print(sum(ran));
# 	print(ran.find(5))
	# print(max(ran),min(ran))
	# print(ran.count(1))
	# print(ran.index('a'))
	# *a,b=ran  ;print(a,b)

	# for n,m in enumerate(ran):
	# 	print(n,m)
# 	print(int(ran))
# print(isinstance(dict1,tuple))
# def B(a):
# if isinstance(dict1,dict):
		# c=a.values()
# if type(dict1) is dict:
# 	print('对')
# B(dict1)